用shell写的递归遍历目录的脚本,脚本实现递归遍历指定目录,打印目录下的文件名。

实例1

#!/bin/sh

function scandir() {
    local cur_dir parent_dir workdir
    workdir=$1
    cd ${workdir}
    if [ ${workdir} = "/" ]
    then
        cur_dir=""
    else
        cur_dir=$(pwd)
    fi

for dirlist in $(ls ${cur_dir})
    do
        if test -d ${dirlist};then
            cd ${dirlist}
            scandir ${cur_dir}/${dirlist}
            cd ..
        else
            echo ${cur_dir}/${dirlist}
        fi
    done
}

if test -d $1
then
    scandir $1
elif test -f $1
then
    echo "you input a file but not a directory,pls reinput and try again"
    exit 1
else
    echo "the Directory isn't exist which you input,pls input a new one!!"
    exit 1
fi

实例2:递归读取目录及其子目录

#! /bin/bash
function read_dir(){
    for file in `ls $1`
    do
        if [ -d $1"/"$file ]  //注意此处之间一定要加上空格,否则会报错
        then
            read_dir $1"/"$file
        else
            echo $1"/"$file
        fi
    done
}

#测试目录 test
read_dir test

这样给test.sh加上执行权限即可执行

$ chmod +x test.sh
$ sh test.sh

到此即可通过传递参数来读取目录文件了。

实例3

递归实现各个子目录孙目录......

#!/bin/bash

#modify.func

doit()   //处理当前目录下的非目录文件,忽略目录文件

{

oldname=`ls | grep "$1$"`

for name in $oldname

do

if [ -d "$name" ]

then :

else

basename=`echo $name | awk -F "." '{print $1}'`

newname="$basename$2"

echo -e "$PWD/$name\t\t$newname"

mv $name $newname

count=`expr ${count} + 1`

fi

done

return 0

}

do_recursive()          //从当前目录开始,递归处理各目录

{

doit $1 $2

for filename in `ls`

do

if [ -d "$filename" ]

then

cd $filename

do_recursive $1 $2

cd ..

fi

done

return 0

}

modify()                     //处理当前目录,并报告结果,这个相当于主函数,也可以直接调用do_recursive

{

PARAMS=2

if [ $# -ne $PARAMS ]

then

echo "usage: mv_to .suf1 .suf2"

return 1

fi

count=0

do_recursive $1 $2

echo "complete! $count files have been modified."

return 0

}